![]() ![]() I can't help with the matlab notation unfortunaly. That way you can simulate nested for loops that begin somewhere in the table and finish not at the end. You can do it in such way that you can start with any value of the number and increase/decrease the digits by any numbers. So you can write the code for increasing such n-digit number. We have to increase the number, so we would get the sequence 0 0 0 We have 3 digit number, with 3 digits for first, 4 for second and five for third digit ![]() ![]() To simulate this you would have to use the "n-digit number notation" In "for notation" we have: for(int x=0 x<3 x ) Suppose we had array(matrix) int T=new int Iterating through n-dimmensional array can be seen as increasing the n-digit number.Īt each dimmension we have as many digits as the lenght of the dimmension. OutArgs = cellfun(fcn, A, 'UniformOutput', false) This is done by calling either arrayfun or cellfun with an additional parameter/value pair: outArgs = arrayfun(fcn, A, 'UniformOutput', false) if my_func returns outputs of different sizes and types when it operates on different elements of A, then outArgs will have to be made into a cell array. If there are any outputs from my_func, these are placed in outArgs, which will be the same size/dimension as A. The function my_func has to accept A as an input. If A is a cell array of arbitrary dimension, you can use cellfun to apply my_func to each cell: outArgs = cellfun(fcn, A) Norm of symbolic vector or matrix - MATLAB norm Documentation Examples. You first create a function handle to this function: fcn = A is a matrix (of type double, single, etc.) of arbitrary dimension, you can use arrayfun to apply my_func to each element: outArgs = arrayfun(fcn, A) Use vecnorm to treat a matrix or array as a collection of vectors and calculate. Let's first assume you have a function that you want to apply to each element of A (called my_func). There are also a couple of functions you can use: arrayfun and cellfun. (Though I don't use a 64 bit MATLAB release, I believe that problem has been resolved for those lucky individuals who do.)Īs pointed out in a few other answers, you can iterate over all elements in a matrix A (of any dimension) using a linear index from 1 to numel(A) in a single for loop. It is really only an issue if you use sparse matrices often, when occasionally this will cause a problem. So if your array has more then a total of 2^32 elements in it, the linear index will fail. MATLAB uses a 32 bit integer to store these indexes. The only problem with the linear index is when they get too large. So you can use it on structures, cell arrays, etc. The linear index applies in general to any array in matlab. Conversion between the linear index and two (or higher) dimensional subscripts is accomplished with the sub2ind and ind2sub functions. There are many circumstances where the linear index is more useful. For example, if we wanted to square the elements of A (yes, I know there are better ways to do this), one might do this: B = zeros(size(A)) The result is, we can access each element in turn of a general n-d array using a single loop. In fact, the function find returns its results as a linear index. A(:)Īs you can see, the 8th element is the number 7. Scalable Vector Graphics (SVG) Export of Figures Converts 2D
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